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Show that 12n cannot end with the digit 0

WebDec 23, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number Get the answers you need, now! vemularama2006 vemularama2006 12/23/2024 Mathematics High School ... Advertisement Brainly User Brainly User Answer: Step-by-step explanation: It can end with a 0. For example 12 * 5 = 60. Advertisement Advertisement New questions in … WebVideo Title:-Check Whether/ Show that 6n or 4n or 12n Can End with the Digit 0 for any natural number n. Fundamental Theorem of ArithmeticFundamental Theo...

Show that 12^n cannot end with the digit 0 or 5 for any …

WebSolution Verified by Toppr If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so … WebApr 19, 2013 · Now, 3^n will never have 0 at the one's digit and the same is true for 4^n. So, 12^n can never end with digit 0 for any natural number n. Answered by 19 Apr, 2013, 07:02: PM careersource job fair tallahassee https://eyedezine.net

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WebDec 23, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number Get the answers you need, now! vemularama2006 vemularama2006 12/23/2024 Mathematics … WebApr 2, 2012 · Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12 n cannot end with the digit 0 or 5. Hope it helps!! This conversation is already closed by Expert Was this answer helpful? 208 View Full Answer WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n Since, 5 is not the factor of 12 n Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n cannot end with the digit 0 or 5 for any value of n. Disclaimer: The question is: 12 n cannot end with the digit 0 or 5 for _______ value of n. Suggest Corrections 1 brooklyn psychotherapy

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Show that 12n cannot end with the digit 0

Show that 12 square n cannot end with the digit 0 or 5 for any …

WebMar 29, 2024 · Ex 1.2 , 5 Check whether 6n can end with the digit 0 for any natural number n. Let us take the example of a number which ends with the digit 0 So, 10 = 2 5 100 = 2 2 5 5 … WebApr 9, 2024 · EXAMPLE 5 Show that 1 2 n cannot en SOLUTION Expressing 12 as the product of primes, we obtain 12 ⇒ 1 2 n = 2 2 × 3 = (2 2 × 3) n = (2 2) n × 3 n = (2) 2 n × 3 n So, only primes in the factorisation of 1 2 n are 2 and 3 and, not 5 . Hence, 1 2 n cannot end with digit 0 or 5. LEVEL-2 EXAMPLE 6 Show that thereare infinitely many positive ...

Show that 12n cannot end with the digit 0

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WebIf 12 n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12 n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 2 2 × 3 ⇒ 12 n = … WebSolution. If any number ends with the digit 0 or 5. It is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of …

WebToppr WebIf 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. ⇒ 12n = (22 × …

Web8 rows · Mar 17, 2024 · SHORT ANSWER TYPE QUESTIONS-I 18. Show that 1 2 n cannot end with the digit 0 or 5 for any natural ... WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 …

WebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime …

WebApr 2, 2012 · Here, Number=12 n where n stand for any natural number . Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with … careersource job trainingWebIf any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3n Since its prime factorisation does not contain 5. brooklyn psychotherapy bay ridgeWebShow that 12^n cannot end with the digit 0 or 5 for any natural number n. http://wp.me/p5C9z4-jd career source kissimmee florida phone numberWeb12 ka factor2×2×3ha or jo digit 0 sa end hota ha 2 or 5 come complesari ha. 1Thank You. Natasha Sharma 3 years, 8 months ago. 12n can be written as (3×4)n and 3 and 4 are the factors of 12 and 5 is not the factor so 11n can nvr end with 0. 0Thank You. careersource lakelandWebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12^n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3^n [since, there is no term contains 5] career source key west flWebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n. Since, 5 is not the factor of 12 n. Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n … careersource kissimmee flWebMar 19, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number n. Viewed by: 5,029 students Updated on: Mar 19, 2024 1 student asked the same question on Filo Learn from their 1-to-1 discussion with Filo tutors. 3 mins Uploaded on: 3/19/2024 Taught by Adarsh Tiwari Connect instantly with this tutor Connect now careersource lake city florida